A chain of 125 links is 1.25m long and has a mass of 2kg. With the ends fastened together, it is set rotating at 3000 rpm. The centripetal force(in N) on each link is( consider π=3.14)
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Solution
Mass of each link, m=2125kg Radius, r=1.252πm Angular velocity, ω=2π×300060rad s−1=100πrad s−1 Centripetal force F=mrω2 or F=2125×1.252π×(100π)2 =1100π×100π×100π =100π=100×3.14=314 N