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Question

A chain of 125 m links in 1.25 m long and has a mass of 2 kg. With the ends fastened together, it is set rotating at 3000rev/min. The centripetal force on each link is :

A
3.14 N
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B
314 N
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C
13.14 N
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D
1314 N
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Solution

The correct option is A 314 N
Given,

ω=3000 rev/min

ω=3000×2π60=100πrad/s

Mass of each link, m=2125kg

Length of chain, L=2πr=1.25

radius, r=1.252πm

The total centripetal force,

F=mω2r

F=2125×100×100π2×1.252π

F=314N

The correct option is B.

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