A chain of mass m and length $L$ is over hanging from the edge of a smooth horizontal table such that $3 / 4^{t h}$ of its length is lying on the table. The work done in pulling the chain completely on to the table is:

\frac{m g L}{16}

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\frac{m g L}{32}

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\frac{3 m g L}{32}

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\frac{m g L}{8}

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Solution

The correct option is D $\frac{m g L}{32}$
W.D $= Δ (P . E)$
$=$ mass of hanging part $\times$ height of COM of hanging part $\times g$
$= \frac{m}{4} \times \frac{L}{8} \times g = \frac{m g L}{32}$

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A chain of mass m and length L is over hanging from the edge of a smooth horizontal table such that 3/4th of its length is lying on the table. The work done in pulling the chain completely on to the table is:

The correct option is D mgL32W.D =Δ(P.E) = mass of hanging part × height of COM of hanging part ×g =m4×L8×g=mgL32

A chain of mass m and length $L$ is over hanging from the edge of a smooth horizontal table such that $3 / 4^{t h}$ of its length is lying on the table. The work done in pulling the chain completely on to the table is:

The correct option is D $\frac{m g L}{32}$
W.D $= Δ (P . E)$
$=$ mass of hanging part $\times$ height of COM of hanging part $\times g$
$= \frac{m}{4} \times \frac{L}{8} \times g = \frac{m g L}{32}$