A chair is $5$ feet from one wall of a room and $7$ feet from the wall at a right angle to it. How far is the chair from the intersection of the two walls?

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Solution

From intersection point , the distance of chair is $\sqrt{7^{2} + 5^{2}} = \sqrt{74}$

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A chair is 5 feet from one wall of a room and 7 feet from the wall at a right angle to it. How far is the chair from the intersection of the two walls?

From intersection point , the distance of chair is √72+52=√74

A chair is $5$ feet from one wall of a room and $7$ feet from the wall at a right angle to it. How far is the chair from the intersection of the two walls?

From intersection point , the distance of chair is $\sqrt{7^{2} + 5^{2}} = \sqrt{74}$