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Question

A charge 109 C is located at the origin of a coordinate system and another charge Q at (2,0,0). If the x component of the electric field at (3,1,1) is zero, calculate the value of Q.

A
4.3×1010 C
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B
2.3×1010 C
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C
4.3×1010 C
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D
2.3×1010 C
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Solution

The correct option is C 4.3×1010 C

Electric field due to a point charge qi at position ri in vector form is expressed as
Ei=kqr3iri

Here,
r1=(30)^i+(10)^j+(10)^k=3^i+^j+^k
& r1=32+12+12=11 m

r2=(32)^i+(10)^j+(10)^k=1^i+1^j+1^k
& r2=12+12+12=3 m

Thus, electric fields due to the charges are,
E1=k×109113/2[3^i+^j+^k]
E2=k×Q33/2[^i+^j+^k]

According to the given condition, Ex=0
Ex1+Ex2=0
3k×109113/2=k×Q33/2
Q=4.3×1010 C

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