Question

A charge of 1000 C flows through a conductor for 3 minutes and 20 seconds. Find the magnitude of current flowing through the conductor:

• A. 5 A
• B. 2 A
• C. 0.5 A
• D. 10 A

Answer 1

The correct option is A 5 A

Current flowing through a conductor is
$I=\frac{Q}{t}$
Where $Q=$ net charge flowing, $t=time$ taken for net charge to flow,
$Q=1000C$
$t=3min20sec,200sec,$
$\therefore I=\frac{1000C}{200sec}=5A$