A charge of $2 μ C$ is taken from infinity to a point in an electric field, without changing the speed. If work done by electric force is $40 μ J,$ then determine the potential at a specified point.

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Solution

Given data:
Charge, $q = 2 μ C$ is taken from $\infty$ to a point.
Work done by electric force is $40 μ J$ .
Formula used:
Thus the relation for work done by external force is given by
$- \frac{W_{e x t (\infty \to p o int)}}{q} = V_{p} - V_{\infty}$
Determine the potential at specific point:
Since, we take $V_{\infty} = 0$
$\Rightarrow - \frac{W_{e x t (\infty \to p o int)}}{q} = V_{p} . . . . (1)$
Since the work done against electrostatic forces is $40 μ J,$ it suggests that $W_{e x t} = 40 μ J$
From Equation $(1)$
$\frac{- 40 μ J}{2 μ C} = V_{p}$
Therefore, $V_{p} = - 20 V$
Final Answer:
The potential at a specific point is $- 20 V .$

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A charge of 2μC is taken from infinity to a point in an electric field, without changing the speed. If work done by electric force is 40μJ, then determine the potential at a specified point.

A charge of $2 μ C$ is taken from infinity to a point in an electric field, without changing the speed. If work done by electric force is $40 μ J,$ then determine the potential at a specified point.