Question

A charge of $2\times {10}^{-2}C$ moves at $30$ revolutions per second in a circle of diameter $80cm$. The current linked with the circuit is

• A. 0.6 A
• B. 1.6 A
• C. 0.2 A
• D. 1.2 A

Answer 1

The correct option is A

0.6 A

We know that,

$I=\frac{Q}{t}$

The charge in the circuit takes $1s$ to complete $30$ revolutions.

So for $1$ revolution, it will take $1/30s$.

$I$ = $\frac{2\times {10}^{-2}}{\frac{1}{30}}$ = $0.6A$