Question

A charge of $20$ $\mu C$ is placed on the positive plate of an isolated parallel-plate capacitor of capacitance $10$ $\mu F$. Calculate the potential difference developed between the plates.

Answer 1

Given:

The charge on the positive plate is $Q=20$ $\mu C$

The capacitance of the capacitor is $C=10$ $\mu F$

The charge on a capacitor is given by:

$Q=CV$

$V=\frac{Q}{C}$

$⟹V=\frac{20}{10}$

$⟹V=2V$