Question

A charge of $24\mu C$ is given to a hollow metallic sphere of radius of $0.2cm$ Find the potential
(i) At the surface of the sphere, and
(ii) At a distance of $0.1cm$ from the centre of the sphere.

Answer 1

(i)

The potential at the sphere’s surface is given as,

$V=\frac{1}{4\pi {\epsilon }_0}\times \frac{q}{r}$

$V=9\times {10}^9\times \frac{24\times {10}^{-6}}{0.2\times {10}^{-2}}$

$V=1.08\times {10}^{8}V$

(ii)

Since the potential at any point inside the sphere will be equal to the potential at the surface.

The potential at $0.1cm$ from the centre of the sphere is given as,

$V=1.08\times {10}^{8}V$