A charge of $4 μ C$ is placed in a uniform electric field of intensity $100 N / C$ . The force acting on the charge is :

25 \times 10^{6} N

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4 \times 10^{- 4} N

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4 \times 10^{4} N

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25 \times 10^{- 6} N

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Solution

The correct option is A $4 \times 10^{- 4} N$
We know force = qE
$= 100 \times 4 \times 10^{- 6}$
$= 4 \times 10^{- 4} N$

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A charge of 4μC is placed in a uniform electric field of intensity 100N/C. The force acting on the charge is :

The correct option is A 4×10−4NWe know force = qE=100×4×10−6=4×10−4N

A charge of $4 μ C$ is placed in a uniform electric field of intensity $100 N / C$ . The force acting on the charge is :

The correct option is A $4 \times 10^{- 4} N$
We know force = qE
$= 100 \times 4 \times 10^{- 6}$
$= 4 \times 10^{- 4} N$