A charge of 5 C experience a force of 5000N when it is kept in a uniform electric field. What is the potential difference between two points separated by a distance of 1 cm
Given,
Electrostatic Force F=qE ......(1)
Where,
q= charge
E=electric field
Potential difference V=Ed ...... (2)
Where,
E=Electric field
d=seperation
From (1) and (2)
V=Fdq=5000×0.015=10V
Hence, what is the potential difference between two points separated by a distance of 1cm is 10V