A charge of 5μ C is placed at the center of a square ABCD of side 10 cm. Find the work done (in μJ) in moving a charge of 1μC from A to B.
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Solution
For a square ABCD, OA=OB=OC=OD=r As charge 5μC is placed on center O so every point A,B,C and D have same potential V=5k/r. Thus potential difference (dV) between A and B will be zero. Work done W=qdV=1(0)=0