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Question

A charge particle having charge q is accelerated through a potential difference V and then it enters a perpendicular magnetic field in which it experiences a force F. If V is increased to 5V, the particle will experience a force

A
F
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B
5F
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C
F5
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D
5F
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Solution

The correct option is D 5F
12mv2=qVv=2qVm. Also F=qvB
F=qB2qVm hence FV which gives F=5F.

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