A charge particle is released from rest in a region of steady and uniform electric and magnetic fields which are parallel to each other. The particle will move in a

Straight line

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Circle

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Helix

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Cycloid

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Solution

The correct option is A Straight line
Force on charge q due to the electric field $¯ E,_{1} = q ¯ E$
Force due to the magnetic field $¯ B,_{2} = q ¯ v \times ¯ B$
$= q v B s i n 0^{\circ}$
= 0
Net force on the charge q, $¯ F =_{1} +_{2} = q ¯ E + 0 = q ¯ E$
Thus the charged particle will move in a straight line
Hence the correct answer is option 1.

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