A charge particle of charge q = 2 C has velocity v=100ms−1. When it passes point A adn has velocity in the direction shown. The strength of magnetic field at the point B due to this moving charge is (r = 2m)
A
2.5μT
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B
5.0μT
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C
2.0μT
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D
None of these
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Solution
The correct option is A2.5μT Given :charge(q)=2C,v=100m/s, r=2m,θ=30v=100ms−1
Solution: We know the formula of magnetic field on moving charge is :
B=μ0M4πr3
And as we know the know the formula of magnetic moment in terms of q &v