Question

A charge particle q of mass m enters a magnetic field B as shown in figure. Speed of charge is V, then d is

• A. $\frac{(\sqrt{3}-1)mV}{4qB}$
• B. $\frac{(\sqrt{3}-1)mV}{5qB}$
• C. $\frac{(\sqrt{3}-1)mV}{3qB}$
• D. $\frac{(\sqrt{3}-1)mV}{2qB}$

Answer 1

The correct option is D $\frac{(\sqrt{3}-1)mV}{2qB}$


$Rsin60-Rsin30=d$
$d=\frac{mV}{qB}(\frac{\sqrt{3}}{2}-\frac{1}{2})$