A charge q=1 $μ$ C is placed at point (1m,2m,4m),. find the electric field at point P(0m,-4m,3m).

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Solution

Given,
$q = 1 μ C$
The distance between Point $(1, 2, 4)$ and $(0, - 4, 3)$
$\to r = -^i - 6^j -^k$
Magnitude of vector $r$
$r = \sqrt{(- 1)^{2} + (- 6)^{2} + (- 1)^{2}} = \sqrt{38} = 6.16 m$
The electric field at point $(0. - 4, 3)$ is given by
$E = \frac{1}{4 π ε_{0}} \frac{q}{r^{2}}$
$E = 9 \times 10^{9} \times \frac{1 \times 10^{- 6}}{38}$
$E = 236.8 N / c$

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A charge q=1 μC is placed at point (1m,2m,4m),. find the electric field at point P(0m,-4m,3m).

Given,q=1μCThe distance between Point (1,2,4) and (0,−4,3)→r=−^i−6^j−^kMagnitude of vector rr=√(−1)2+(−6)2+(−1)2=√38=6.16mThe electric field at point (0.−4,3) is given byE=14πε0qr2E=9×109×1×10−638E=236.8N/c

A charge q=1 $μ$ C is placed at point (1m,2m,4m),. find the electric field at point P(0m,-4m,3m).