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Law of Conservation of Energy

A charge q = ...

Question

A charge $q = 10^{- 6} C$ of mass $2 g$ is free to move when released at a distance $^{'} a^{'}$ from the fixed charge $Q$ .
Calculate its speed, when it moves to a distance $b$
[Assume $a = 1 m$ , $b = 10 m, Q = 10^{- 3} C]$

90 m/s

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9 m/s

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900 m/s

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None of these

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Solution

The correct option is A $90 m/s$
By work energy theorem
$W = Δ K E \Rightarrow - \frac{K Q q}{b} + \frac{K Q q}{a} = \frac{1}{2} m v^{2}$
$v = \sqrt{\frac{2 K Q q}{m} [\frac{- a + b}{a b}]}$
$v = \sqrt{\frac{2 \times 9 \times 10^{9} \times 10^{- 3} \times 10^{- 6}}{2 \times 10^{- 3}} [\frac{10 - 1}{10}]}$
$v = 90 m/s$

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A charge q=10−6C of mass 2 g is free to move when released at a distance ′a′ from the fixed charge Q. Calculate its speed, when it moves to a distance b [Assume a=1 m, b=10 m,Q=10−3C]

The correct option is A 90 m/sBy work energy theorem W=ΔKE⇒−KQqb+KQqa=12mv2 v=√2KQqm[−a+bab] v=√2×9×109×10−3×10−62×10−3[10−110] v=90 m/s

A charge $q = 10^{- 6} C$ of mass $2 g$ is free to move when released at a distance $^{'} a^{'}$ from the fixed charge $Q$ .
Calculate its speed, when it moves to a distance $b$
[Assume $a = 1 m$ , $b = 10 m, Q = 10^{- 3} C]$