A charge q-2-0 - C is placed at origin- Find the electric field at 3 m- 4 m- 0

E⃗=kq(r⃗)|r⃗|^3 r⃗=3î+4ĵ #160; #160; #160; |r⃗|=5 E⃗=kq(3î+4ĵ)125 E⃗=9× 10^9× ( 2× 10^ 9)(3î+4ĵ)125 E⃗= 0.424î 0.576ĵ ...

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Byju's Answer

Standard XII

Physics

Unit Vectors

A charge q=...

Question

A charge $q = - 2.0 μ C$ is placed at origin. Find the electric field at $(3 m, 4 m, 0)$

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Solution

$\to E = \frac{k q (\to r)}{| \to r |^{3}}$

$\to r = 3^i + 4^j$ $| \to r | = 5$

$\to E = \frac{k q (3^i + 4^j)}{125}$

$\to E = \frac{9 \times 10^{9} \times (- 2 \times 10^{- 9}) (3^i + 4^j)}{125}$

$\to E = - 0.424^i - 0.576^j$

$| \to E | = 0.389$

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