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Question

A charge q=4μC has an instantaneous velocity v=(2^i3^j+^k)×106m/s in a uniform magnetic field B=(2^i+5^j3^k)×102T.What is the force on the charge?

A
(0.16^i0.32^j0.64^k)N
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B
(0.16^i0.12^j0.44^k)N
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C
(0.16^i0.82^j0.44^k)N
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D
(0.12^i0.12^j0.64^k)N
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Solution

The correct option is A (0.16^i0.32^j0.64^k)N
F=qv×B,whereqhasapositiveornegativesign,onsubstituting,weget0.16^i0.32^j+0.64^k

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