A charge q=−4μC has an instantaneous velocity →v=(2^i−3^j+^k)×106m/s in a uniform magnetic field →B=(2^i+5^j−3^k)×10−2T.What is the force on the charge?
A
(−0.16^i−0.32^j−0.64^k)N
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B
(−0.16^i−0.12^j−0.44^k)N
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C
(−0.16^i−0.82^j−0.44^k)N
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D
(−0.12^i−0.12^j−0.64^k)N
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Solution
The correct option is A(−0.16^i−0.32^j−0.64^k)N →F=q→v×→B,whereqhasapositiveornegativesign,onsubstituting,weget−0.16^i−0.32^j+−0.64^k