A charge $q$ coulomb moves in a circle at $n$ revolutions per second and the radius of the circle is $r$ metre. Then magnetic field at the center of the circle is

\frac{2 π q}{n r} \times 10^{- 7} N A^{- 1} m^{- 1}

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\frac{2 π q}{r} \times 10^{- 7} N A^{- 1} m^{- 1}

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\frac{2 π n q}{r} \times 10^{- 7} N A^{- 1} m^{- 1}

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\frac{2 π q}{r} N A^{- 1} m^{- 1}

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Solution

The correct option is C $\frac{2 π n q}{r} \times 10^{- 7} N A^{- 1} m^{- 1}$
$B = \frac{μ_{0} I}{2 r} o r B = \frac{μ_{0} q}{2 r T}$

$B = \frac{4 π \times 10^{- 7} \times q}{2 r} n$

$B = \frac{2 π n q}{r} \times 10^{- 7} N A^{- 1} m^{- 1}$

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A charge q coulomb moves in a circle at n revolutions per second and the radius of the circle is r metre. Then magnetic field at the center of the circle is

The correct option is C 2πnqr×10−7NA−1m−1B=μ0I2rorB=μ0q2rTB=4π×10−7×q2rnB=2πnqr×10−7NA−1m−1

A charge $q$ coulomb moves in a circle at $n$ revolutions per second and the radius of the circle is $r$ metre. Then magnetic field at the center of the circle is

The correct option is C $\frac{2 π n q}{r} \times 10^{- 7} N A^{- 1} m^{- 1}$
$B = \frac{μ_{0} I}{2 r} o r B = \frac{μ_{0} q}{2 r T}$

$B = \frac{4 π \times 10^{- 7} \times q}{2 r} n$

$B = \frac{2 π n q}{r} \times 10^{- 7} N A^{- 1} m^{- 1}$