A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will
A
be reduced to half
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B
remain the same
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C
be doubled
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D
become four times
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Solution
The correct option is B remain the same We know from Gauss's law that the electric flux through any closed spherical surface is given by
ϕ=qenclosedϵ0
As we can see it is independent of the radius of the closed surface and only depends on the charge enclosed.
Therefore if the radius of Gaussian spherical surface is doubled then there will be no effect on flux and the outward electric flux will remain the same.