A charge Q is placed at a distance a/2 above the centre of the square surface of edge a as shown in the figure. The electric flux through the square surface is :
A
Q3ϵ0
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B
Q6ϵ0
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C
Q2ϵ0
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D
Qϵ0
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Solution
The correct option is BQ6ϵ0
A charge Q is placed at a distance =a/2
the centre of the square surface of edge a as shown in figure. The electric flux through the square surface. Due to symmetry electric field flux through that surface should be ϕ=Q6ϵo