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Question

A charge q is placed at one corner of a cube as shown in figure. The flux of electrostatic field E though the shaded area is:

A
q48ϵo
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B
q8ϵo
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C
q24ϵo
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D
q4ϵo
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Solution

The correct option is C q24ϵo
Total flux through the cube =qϵo×18=q8ϵo

Total flux through one “outer” face of the cube =q8ϵo×13=q24ϵo
[Because there is flux only through 3 faces]

Hence, total flux through shaded area,
ϕT=(q24ϵo+q24ϵo)×12
[half of each face is shaded]

ϕT=q24ϵo

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