A charge q is placed at one corner of a cube. The electric flux through any of the three faces adjacent to the charge is zero. The flux through any one of the other three faces is.
A
q/3ϵ0
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B
q/6ϵ0
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C
q/12ϵ0
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D
q/24ϵ0
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Solution
The correct option is Dq/24ϵ0 ACCORDING TO THE GIVEN PROBLEM, THE CHARGE IS PLACED AT THE CORNER OF THE CUBE AS SHOWN IN FIGHURE_1,
NOW CONSIDER THE ANOTHER FIGURE_2 IN WHICH THE WHOLE CHARGE IS ENCLOSED IN THE FOUR SUCH CUBE,
NOW CALCULATING THE FLUX THROUGH THE ALL CUBES AS TOTAL:
ϕe=qϵ0=EA
WHERE A=6∗(2a)2
FOR ONLY ONE SIDE OF FIRST CUBE,
AREA WILL BE A0=a2
FROM ABOVE DATA FLUX THROW THE SINGLE FACE (AREA = A0 ) IS GIVEN BY:
ϕe=Qϵ0=EA0
WHERE Q=q24
SO THE FLUX THROUGH THROUGH THE SINGLE FACE IS q24ϵ0 ;