A charge Q is placed at the centre O of a square ABCD of side a as shown in Fig. 20.15. The work done to move a charge q from A to B is
A
qQ4πϵ0a
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B
√2qQ4πϵ0a
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C
qQ2πϵ0a
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D
Zero
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Solution
The correct option is D Zero Work done =charge × potential difference. WA→B=q(VB−VA) Since points A and B are at the same distance from charge Q, VA=VB. Hence, work done is zero, which is choice (d)