A charge Q is placed at the corner of a cube. The electric flux through all the faces of the cube is:
A
Q/ε0
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B
Q/6ε0
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C
Q/8ε0
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D
Q/3ε0
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Solution
The correct option is DQ/8ε0 Let us add 7 more cubes of same size as above and make Q placed at center of large cubes with side 2a. Now there are 8 cubes covering Q.
So, flux coming out will be divided equally as Q is symmetrically placed. ∴ flux through any one of the cubes =Q8ξ0