Question

A charge $Q$ is placed in a medium of dielectric constant $K$. The maximum number of lines of force are :

• A. $\frac{Q}{{\epsilon }_0}$
• B. $\frac{Q}{K}$
• C. $\frac{Q}{K{\epsilon }_0}$
• D. $0$

Answer 1

The correct option is C $\frac{Q}{K{\epsilon }_0}$

In dielectrics, the electric field produced by the charge is reduced i.e. no of electric lines of forces are reduced by a factor K due to polarization of the dielectric medium.
According to Gauss law, no of electric lines produced in vacuum is equal to $\frac{Q}{{\epsilon }_o}$.

So the no of electric lines of force produced in a dielectric of dielectric constant K is equal to $\frac{Q}{K{\epsilon }_o}$.