A charge $Q$ is placed inside the sphere of radius $a$ then electric potential (magnitude) at the surface of the sphere will be, (symbols have their usual meaning)

\frac{K Q}{a}

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\frac{2 K Q}{a}

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\frac{\frac{1}{2} K Q}{a}

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Solution

The correct option is A $\frac{K Q}{a}$
We know that the charge inside a conductor is zero. When a charge $Q$ is placed inside the conductor, $- Q$ will induce on inner surface and $+ Q$ will induce on outer surface such that total charge inside the conductor is zero.
Thus, the charge accumulated on the surface of sphere will be $Q$ .
For a spherical conductor, the electric potential at surface $=$ the electric potential inside sphere $= \frac{k Q}{a}$

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A charge Q is placed inside the sphere of radius a then electric potential (magnitude) at the surface of the sphere will be, (symbols have their usual meaning)

A charge $Q$ is placed inside the sphere of radius $a$ then electric potential (magnitude) at the surface of the sphere will be, (symbols have their usual meaning)