A charge $Q$ is uniformly distributed over a large plastic sheet. The electric field at a point $P$ close to the centre of the sheet is $10 N/C$ . If the plastic sheet is replaced by a copper sheet of the same geometrical dimensions and carrying the same charge $Q$ , the electric field at the point $P$ will become

Zero

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5 N/C

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10 N/C

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20 N/C

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Solution

The correct option is C $10 N/C$
We know that, electric field near a large charged sheet is given by
$E = \frac{σ}{2 ϵ_{0}} = \frac{Q}{2 A ϵ_{0}}$
As in the given problem, charge and dimensions of both sheets are the same, therefore charge density $(σ)$ is also same.
Hence, electric field will also be equal for both sheets.

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Standard XII Physics

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The correct option is C 10 N/CWe know that, electric field near a large charged sheet is given by E=σ2ϵ0=Q2Aϵ0 As in the given problem, charge and dimensions of both sheets are the same, therefore charge density (σ) is also same. Hence, electric field will also be equal for both sheets.