A charged particle (charge q, mass m) has velocity v0 at the origin in +x direction. In space, there is a uniform magnetic field B in –z direction. Find the y coordinate of the particle when it crosses y axis.
A
2mv0qB
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B
mv0qB
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C
4mv0qB
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D
None of these
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Solution
The correct option is A2mv0qB Force on a charged particle in the magnetic field F=q(→v×→B) F=qvBsinθ ∵ here v and B are perpendicular, therefore θ=90∘ F=qvB(1)
It is equal to centripetal force mv2R...(2) ∴ from equation (1) and (2) qvB=mv2R (here v=v0) R=mv0qB
Now y coordiante will be (0,2R)
i.e., 2mv0qB