A charged particle enters a uniform magnetic field with velocity vector at an angle of 45 degree with a magnetic field the pitch of the helical path is P the radius of the helix will be

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Dear Student,
$t i m e p e r i o d o f o n e r e v o l u t i o n, l e t r a d i u s b e r T = \frac{2 πr}{v \cos 45} P i t c h o f h e l i x i s P = \frac{2 πr}{v \cos 45} \times v \sin 45 = 2 πr r = \frac{P}{2 π} R e g a r d s$

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A charged particle enters a uniform magnetic field with velocity vector at an angle of 45 degree with a magnetic field the pitch of the helical path is P the radius of the helix will be

Dear Student, time period of one revolution, let radius be r T=2πrvcos 45Pitch of helix is P=2πrvcos 45×vsin45=2πrr=P2πRegards

Dear Student,
$t i m e p e r i o d o f o n e r e v o l u t i o n, l e t r a d i u s b e r T = \frac{2 πr}{v \cos 45} P i t c h o f h e l i x i s P = \frac{2 πr}{v \cos 45} \times v \sin 45 = 2 πr r = \frac{P}{2 π} R e g a r d s$