A charged particle enters in uniform magnetic at an angle $t a n^{- 1} {2 π}$ . This angle is between velocity vector and magnegtic field vector. Its path becomes helix with radius of path ‘r” and pitch of “p”, then

p = \sqrt{3} r

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p = \frac{r}{\sqrt{3}}

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p = r

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p = \frac{r}{\sqrt{2}}

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Solution

The correct option is C p = r
$r = \frac{m v s i n θ}{q B}$
$p = \frac{2 π m v c o s θ}{q B}$
$\frac{p}{r} = \frac{t a n θ}{2 π} = \frac{2 π}{2 π} = 1$
p = r

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The correct option is C p = r
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