MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Desciption of Force

A charged par...

Question

A charged particle goes undeflected in a region containing electric and magnetic fields. It is possible that

A

\to E ∥ \to B, \to v ∥ \to E

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

\to E

is parallel to

\to B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

\to v ∥ \to E

also

\to E

is not parallel to

\to B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

\to E ∥ \to B

but

\to v

is not parallel to

\to E

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\to v ∥ \to E$ also $\to E$ is not parallel to $\to B$
If the magnetic force on the particle is zero, a charged particle goes undeflected in a region containing electric and magnetic fields and $\to v ∥ \to E$ . Also, $\to E$ is not parallel to $\to B$ .

Suggest Corrections

thumbs-up

0

Similar questions

Q. A charged particle with charge

q

enters a region of constant, uniform and mutually orthogonal fields

\to E

\to B

, with a velocity

\to v

perpendicular to both

\to E

\to B

, and comes out without any change in magnitude or direction of

\to v

Q. A charged particle goes undeflected in a region of space containing an electric field

\to E

and a magnetic field of intensity

\to B

. Which of the following is possible?

Q. In cyclotron we apply electric field(

\to E

) & magnetic field(

\to B

) to accelerate the charged particles or ions, where

\to E

\to B

Q. A particle of mass m and charge q is moving in a region where uniform, constant electric and magnetic fields

\to E

\to B

\to E

\to B

are parallel to each other. At time

t = 0

{\to v}_{0}

of the particle is perpendicular to

\to E

(Assume that its speed is always < < c, the speed of light in vacuum). If the velocity

\to v

of the particle at time t is

\to v = X \times c o s (\frac{q B}{m} t) ({\to v}_{0}) + (\frac{q}{m} t) (\to E) + X \times s i n (\frac{q B}{m} t) (\frac{{\to v}_{0} \times \to B}{B})

Q. A charged particle with charge

q

enters a region of constant uniform and mutually orthogonal fields

\to E

\to B

with a velocity

\to v

perpendicular to both

\to E

\to B

and comes out without any change in magnitude and direction of

\to v

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Charge Motion in a Magnetic Field

PHYSICS

Watch in App

explore_more_icon

Explore more

Desciption of Force

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon