A charged particle goes undeflected in a region of space containing an electric field →E and a magnetic field of intensity →B. Which of the following is possible?
A
→E is parallel to →B but →v is perpendicular to →E
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
→E is parallel to →B and →v parallel to →E
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
→E is perpendicular to →B and →v is parallel to →E×→B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
→E is perpendicualar to →B and →v is parallel to →E.→B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are B→E is parallel to →B and →v parallel to →E C→E is perpendicular to →B and →v is parallel to →E×→B From Lorentz force, −→FL=→Fe+−→Fm →Fe = electric force −→Fm = magnetic force −→FL=q→E+q(→v×→B)
If →E||→B and →v||→E, then →v must be parallel to →B. ∴−→FL=q→E+0=q→E Charge will either accelerate or decelerate in the same direction of →v, but does not deflect.
If →E is perpendicular to →B and →v is parallel to →E×→B ⇒→E,→B and →v are mutually perpendicular to each other. ⇒→v×→B=k→E
−→FL=q→E+q(→v×→B) −→FL=q→E+qk→E For k=−1,FL=0 Hence, its possible for charge to travel undeflected.