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Question

A charged particle having a charge of 2.o×106C is placed close to a nonconducting plate having a surface charge density 4.0×106 C m2. Find the force of attraction between the particle and the plate.

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Solution

We know that E due to conducting charge density

E=σ2 0

Then F=qE=qσ2 0

=2.0×106×4.0×1062×8.8×1012

=0.45N.


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