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Magnetic Field

A charged par...

Question

A charged particle is accelerated through a potential difference of 12 KV and aquires a speed of 1 ×10^6 m/s . It is then injected perpendicularly into a magnetic field of strength 0.2T . Find the radius of the circle described by it.

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Solution

centripetal force = mv^2 / r
= magnetic force = qvB

Solve for your radius:
r = mv / qB

You know v and B, but not q or m.

initial KE = qV = kinetic energy = 1/2 mv^2

m/q = 2V / v^2

plug that into your radius equation:
r = 2V / Bv

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