Question

A charged particle is projected perpendicular to a uniform electric field of length $2\text{m}$ and initial velocity of charged particle is $10\text{m/s}$. Calculate deflection of the charge in the direction of electric field., when it leaves it.

• A. $4\text{mm}$
• B. $6\text{mm}$
• C. $8\text{mm}$
• D. $9\text{mm}$

Answer 1

The correct option is A $4\text{mm}$

Time taken to cross electric field region
$t=\frac{d}{v}=\frac{2}{10}=0.2\text{sec}$
Acceleration of particle in direction of E.F
$a=\frac{qE}{m}=\frac{2\times {10}^{-5}\times 100}{{10}^{-2}}=0.2{\text{m/s}}^2$

Using $y=ut+\frac{1}{2}a{t}^2$
$y=0+\frac{1}{2}\times 0.2\times (0.2{)}^2$
$y=4\times {10}^{-3}$
$y=4\text{mm}$ is the defelection in the direction of E.F