A charged particle is projected with velocity υ₀ along positive x-axis. The magnetic field B is directed along negative z-axis between x = 0 and x = L. The particle direction of projection. Find the velocity with which the same particle is projected (at x = 0) along positive x - axis so that when it emerges out (at x = L), the angle made by it is 30⁰ with the direction of projection

$2 v_{0}$

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$\frac{v_{0}}{2}$

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$\frac{v_{0}}{\sqrt{3}}$

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$\sqrt{3} v_{0}$

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Solution

The correct option is D
$\sqrt{3} v_{0}$

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A charged particle is projected with velocity υ₀ along positive $x -$ axis. The magnetic field $B$ is directed along negative $z -$ axis between $x = 0$ and $x = L$ . The particle direction of projection. Find the velocity with which the same particle is projected (at $x = 0$ ) along positive $x -$ axis so that when it emerges out (at $x = L$ ), the angle made by it is $30^{\circ}$ with the direction of projection

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