A charged particle is released in non zero uniform magnetic and electric field at different velocities-Assume that E- and B- can be randomly in any direction-The path of charged particle can be

If E⃗ is perpendicular to B⃗ and v = E/B, the particle will move in straight line. If E⃗ is perpendicular to B⃗ and v = 0, then the path will be a cycloid. ...

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Byju's Answer

Standard XIII

Physics

Centripetal Force

A charged par...

Question

A charged particle is released in non zero uniform magnetic and electric field at different velocities.
[Assume that $\to E$ and $\to B$ can be randomly in any direction.]
The path of charged particle can be

Straight line

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Circle

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Parabola

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cycloid

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Solution

The correct option is D cycloid
If $\to E$ is perpendicular to $\to B$ and $v = \frac{E}{B}$ , the particle will move in straight line.

If $\to E$ is perpendicular to $\to B$ and $v = 0$ , then the path will be a cycloid.

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A charged particle is released in non zero uniform magnetic and electric field at different velocities. [Assume that →E and →B can be randomly in any direction.] The path of charged particle can be

The correct option is D cycloidIf →E is perpendicular to →B and v=EB, the particle will move in straight line. If →E is perpendicular to →B and v=0, then the path will be a cycloid.

A charged particle is released in non zero uniform magnetic and electric field at different velocities.
[Assume that $\to E$ and $\to B$ can be randomly in any direction.]
The path of charged particle can be

The correct option is D cycloid
If $\to E$ is perpendicular to $\to B$ and $v = \frac{E}{B}$ , the particle will move in straight line.

If $\to E$ is perpendicular to $\to B$ and $v = 0$ , then the path will be a cycloid.