A charged particle is released in non zero uniform magnetic and electric field at different velocities-Assume that E- and B- can be randomly in any direction-The path of charged particle can be

If E⃗ is perpendicular to B⃗ and v = E/B, the particle will move in straight line. If E⃗ is perpendicular to B⃗ and v = 0, then the path will be a cycloid. ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Physics

Centripetal Force

A charged par...

Question

A charged particle is released in non zero uniform magnetic and electric field at different velocities.
[Assume that $\to E$ and $\to B$ can be randomly in any direction.]
The path of charged particle can be

Straight line

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Circle

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Parabola

No worries! We‘ve got your back. Try BYJU‘S free classes today!

cycloid

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D cycloid
If $\to E$ is perpendicular to $\to B$ and $v = \frac{E}{B}$ , the particle will move in straight line.

If $\to E$ is perpendicular to $\to B$ and $v = 0$ , then the path will be a cycloid.

Suggest Corrections

Similar questions

Q. A charged particle is released in non zero uniform magnetic and electric field at different velocities.
[Assume that

\to E

and

\to B

can be randomly in any direction.]
The path of charged particle can be

A region contains both uniform electric field $\to E$ and uniform magnetic field $\to B$ . A charge particle

Q. A particle moves in a region having a uniform magnetic field and a parallel, uniform electric field. At some instant, the velocity of the charged particle is perpendicular to the field direction. The path of the particle will be

Q. A charged particle moves with a constant velocity

(^i +^j) m / s

in a magnetic field

\to B = (2^i + 3^k)

and uniform electric field

\to E = (a^i + b^j + c^k) N / C

, then

(

assuming all quantities in S.I. unit

) :

Q. A charged particle with charge

q

enters a region of constant uniform and mutually orthogonal fields

\to E

and

\to B

with a velocity

\to v

perpendicular to both

\to E

and

\to B

and comes out without any change in magnitude and direction of

\to v

. Then,

Join BYJU'S Learning Program

A charged particle is released in non zero uniform magnetic and electric field at different velocities. [Assume that →E and →B can be randomly in any direction.] The path of charged particle can be

The correct option is D cycloidIf →E is perpendicular to →B and v=EB, the particle will move in straight line. If →E is perpendicular to →B and v=0, then the path will be a cycloid.

A charged particle is released in non zero uniform magnetic and electric field at different velocities.
[Assume that $\to E$ and $\to B$ can be randomly in any direction.]
The path of charged particle can be

The correct option is D cycloid
If $\to E$ is perpendicular to $\to B$ and $v = \frac{E}{B}$ , the particle will move in straight line.

If $\to E$ is perpendicular to $\to B$ and $v = 0$ , then the path will be a cycloid.