A charged particle moves inside a pipe- which is bent as shown in the figure- If R - mvqB- then the force exerted by the pipe on charged particle at P is Neglect gravity -

The correct option is A toward the centerRadius of the circular path in magnetic field #160; R=mvqB At point P if we neglect weight then the centr ...

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Standard XII

Physics

Electric Field Due to a Sphere and Thin Shell

A charged par...

Question

A charged particle moves inside a pipe, which is bent as shown in the figure. If $R < \frac{m v}{q B}$ , then the force exerted by the pipe on charged particle at $P$ is (Neglect gravity) :

toward the center

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away from the center

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zero

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none of these

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Solution

The correct option is A toward the center
Radius of the circular path in magnetic field $R = \frac{m v}{q B}$
At point $P$ if we neglect weight then the centripetal force is provided by the magnetic force which is towards the center.

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A charged particle moves inside a pipe, which is bent as shown in the figure. If R<mvqB, then the force exerted by the pipe on charged particle at P is (Neglect gravity) :

The correct option is A toward the centerRadius of the circular path in magnetic field R=mvqBAt point P if we neglect weight then the centripetal force is provided by the magnetic force which is towards the center.

A charged particle moves inside a pipe, which is bent as shown in the figure. If $R < \frac{m v}{q B}$ , then the force exerted by the pipe on charged particle at $P$ is (Neglect gravity) :

The correct option is A toward the center
Radius of the circular path in magnetic field $R = \frac{m v}{q B}$
At point $P$ if we neglect weight then the centripetal force is provided by the magnetic force which is towards the center.