A charged particle moves with a uniform velocity 4ax m-s in a region where E-20ay V-m and The value of B0 such that the velocity of the particlr remains constant is

B=B_0 a_z Wb/m^2 As constant velocity hence acceleration is zero F=ma =0=Q[E+V × B] 0=Q[20a_y +4a_x × B_0 a_z] nbsp;nor, nbsp; nbsp; 20a_y = 4B_0 a_ ...

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A charged par...

Question

A charged particle moves with a uniform velocity $4 a_{x}$ m/s in a region where $\to E = 20 a_{y}$ V/m and The value of $B_{0}$ such that the velocity of the particlr remains constant is

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Solution

The correct option is A $5$
$B = B_{0} a_{z} W b / m^{2}$

As constant velocity hence acceleration is zero

$F = m a = 0 = Q [E + V \times B]$

$0 = Q [20 a_{y} + 4 a_{x} \times B_{0} a_{z}]$
nor, $- 20 a_{y} = - 4 B_{0} a_{y}$

$\Rightarrow B_{0} = 5$

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A charged particle moves with a uniform velocity 4ax m/s in a region where →E=20ay V/m and The value of B0 such that the velocity of the particlr remains constant is

The correct option is A 5B=B0azWb/m2 As constant velocity hence acceleration is zero F=ma=0=Q[E+V×B] 0=Q[20ay+4ax×B0az] nor, −20ay=−4B0ay ⇒B0=5

A charged particle moves with a uniform velocity $4 a_{x}$ m/s in a region where $\to E = 20 a_{y}$ V/m and The value of $B_{0}$ such that the velocity of the particlr remains constant is

The correct option is A $5$
$B = B_{0} a_{z} W b / m^{2}$

As constant velocity hence acceleration is zero

$F = m a = 0 = Q [E + V \times B]$

$0 = Q [20 a_{y} + 4 a_{x} \times B_{0} a_{z}]$
nor, $- 20 a_{y} = - 4 B_{0} a_{y}$

$\Rightarrow B_{0} = 5$