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Standard XII

Physics

Flux as the Flow

A charged par...

Question

A charged particle of charge $5$ $m C$ and mass $5$ $g m$ is moving with a constant speed $5$ $m s^{- 1}$ in a uniform magnetic field on a curve $x^{2} + y^{2} = 25$ . Where $x$ and $y$ are in meter. The value of magnetic field is:

1

Tesla

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1

Tesla along z-axis

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5

Kilo Tesla along the x-axis

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1

Kilo Tesla along any line in the x-y plane

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Solution

The correct option is C $1$ Tesla along z-axis
Curve: $x^{2} + y^{2} = 25$
$r = 5 m$
We know,
$r = \frac{m v}{q B}$
$5 = \frac{5 \times 10^{- 3} \times 5}{5 \times 10^{- 3} \times B}$
$B = 1 T$
And B will be perpendicular to the x-y plans.
So $B = 1$ T along z-axis.

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A charged particle of charge 5 mC and mass 5 gm is moving with a constant speed 5 ms−1 in a uniform magnetic field on a curve x2+y2=25 . Where x and y are in meter. The value of magnetic field is:

The correct option is C 1 Tesla along z-axisCurve: x2+y2=25r=5mWe know,r=mvqB5=5×10−3×55×10−3×BB=1TAnd B will be perpendicular to the x-y plans.So B=1 T along z-axis.

A charged particle of charge $5$ $m C$ and mass $5$ $g m$ is moving with a constant speed $5$ $m s^{- 1}$ in a uniform magnetic field on a curve $x^{2} + y^{2} = 25$ . Where $x$ and $y$ are in meter. The value of magnetic field is:

The correct option is C $1$ Tesla along z-axis
Curve: $x^{2} + y^{2} = 25$
$r = 5 m$
We know,
$r = \frac{m v}{q B}$
$5 = \frac{5 \times 10^{- 3} \times 5}{5 \times 10^{- 3} \times B}$
$B = 1 T$
And B will be perpendicular to the x-y plans.
So $B = 1$ T along z-axis.