The correct options are
A Velocity of the particle when it comes out from the magnetic field is
→v=vcos60∘^+v sin60∘^j B Time for which the particle was in magnetic field is
πm3qB C Distance travelled in magnetic field is
πmv3qBThe charge particle
q will experience some force when it moves in the region of magnetic field.
The trajectory of this particle in this region can be shown as below
![](https://search-static.byjusweb.com/question-images/byjus/infinitestudent-images/ckeditor_assets/pictures/627705/original_xc.PNG)
The components of velocity when it exits the magnetic fields are
v cos60∘ and
v sin60∘ along x and y axis respectively.
⟹→v=v sin60∘^i+v cos60∘^j Let us consider a point
C on y-axis which represents the centre of circular track followed by the particle.
r is the radius of the circular track.
From the figure we can calculate
∠ACB=600 t=θω=π3ω mv2r=qvB v=rω ⟹mω=qB ⟹ω=qBm ∴t=πm3qB Distance travelled in magnetic field
l=rθ ⟹l=mvqB×π3 ∴l=mvπ3qB