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Standard XII

Physics

Electric Field

A charged par...

Question

A charged particle of charge $Q$ and mass $m$ moves with velocity $v$ in a circular path due to transverse magnetic field $B$ , then its frequency is

\frac{Q B}{2 π m}

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\frac{Q v B}{2 π m}

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\frac{Q m v B}{2 π}

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\frac{v B}{2 π Q m}

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Solution

The correct option is A $\frac{Q B}{2 π m}$
Magnetic Field $= B$
Centrifugal Force = $\frac{m v^{2}}{R}$
Magnetic Force $= Q v B$
$\frac{m v^{2}}{R} = Q v B$
$v = \frac{Q B R}{m}$
frequency = $\frac{v}{2 π R} = \frac{Q B}{2 π m}$

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A charged particle of charge Q and mass m moves with velocity v in a circular path due to transverse magnetic field B, then its frequency is

The correct option is A QB2πmMagnetic Field =BCentrifugal Force = mv2RMagnetic Force =QvBmv2R=QvBv=QBRmfrequency = v2πR=QB2πm

A charged particle of charge $Q$ and mass $m$ moves with velocity $v$ in a circular path due to transverse magnetic field $B$ , then its frequency is

The correct option is A $\frac{Q B}{2 π m}$
Magnetic Field $= B$
Centrifugal Force = $\frac{m v^{2}}{R}$
Magnetic Force $= Q v B$
$\frac{m v^{2}}{R} = Q v B$
$v = \frac{Q B R}{m}$
frequency = $\frac{v}{2 π R} = \frac{Q B}{2 π m}$