A charged particle of mass 2 mg remains freely in air in an electric field of strength 4 N/C directed upward. Calculate the charge and determine its nature ( g = 10 m/ $s^{2}$ ).

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Solution

$F = m g$ and $F = q E$
So, $q E = m g$
$q = \frac{m g}{E}$
$= \frac{2 \times 10^{-} 6 \times 9.8}{4}$
$= 4.6 \times 10^{- 6}$ C

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A charged particle of mass 2 mg remains freely in air in an electric field of strength 4 N/C directed upward. Calculate the charge and determine its nature ( g = 10 m/s2).

F=mg and F=qESo, qE=mgq=mgE=2×10−6×9.84=4.6×10−6 C

A charged particle of mass 2 mg remains freely in air in an electric field of strength 4 N/C directed upward. Calculate the charge and determine its nature ( g = 10 m/ $s^{2}$ ).

$F = m g$ and $F = q E$
So, $q E = m g$
$q = \frac{m g}{E}$
$= \frac{2 \times 10^{-} 6 \times 9.8}{4}$
$= 4.6 \times 10^{- 6}$ C