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Question

A charged particle of mass m1 and charge q1 is revolving in a circle of radius r. Another charged particle of charge q2 and mass m2 is situated at the centre of the circle. If the velocity and time period of the revolving particle be v and T respectively, then :

A
v=q1q2r4πϵ0m1
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B
v=1m1q1q24πϵ0r
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C
T=16π3ϵ0m21r3q1q2
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D
T=16π3ϵ0m2r3q1q2
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E
None of the above
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Solution

The correct option is D None of the above
Both charges are either both positive or both negative(since answers has the product q1q2inside square root). Hence, circular motion is not possible. So either q1 or q2 should be negative.

According to the diagram,
m1v2r=14πϵ0q1q2r2
v=14πϵ0m1q1q2r
On putting, v=rω and ω=2πT, we can find out:
T=16π3ϵ0m1r3q1q2
Hence, none of the answers is correct.

621692_574048_ans.PNG

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