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Second Law of Motion

A charged par...

Question

A charged particle of mass 'm' and charge 'q' moves with a constant velocity 'V' along the positive 'x' direction . It enters a region of Magnetic field which is directed towards positive 'z' direction which is given by 'b'. Find the radius of the circular path which the particle moves

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Solution

using
qvB=m $V^{2}$ /r
r=mV/qB

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