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Standard XII

Physics

Angular Velocity

A charged par...

Question

A charged particle of mass m and charge q travels on a circular path of radius r that is perpendicular to a magnetic field B.The time taken by the particle to complete one revolution is

\frac{2 π q B}{m}

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\frac{2 π q}{m B}

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\frac{2 π m}{q B}

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\frac{q B}{2 π m}

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Solution

The correct option is C $\frac{2 π m}{q B}$
$Solution :$
Equating magnetic force to centripetal force,we get
$\frac{m v^{2}}{r} = q v B s i n 90^{\circ}$
Also,Time to complete one revolution is given by,
$T = \frac{2 π r}{v} = \frac{2 π m}{q B}$

$Hence C is the correct option$

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A charged particle of mass m and charge q travels on a circular path of radius r that is perpendicular to a magnetic field B.The time taken by the particle to complete one revolution is

The correct option is C 2πmqBSolution:Equating magnetic force to centripetal force,we getmv2r=qvBsin90∘Also,Time to complete one revolution is given by,T=2πrv=2πmqBHence C is the correct option

The correct option is C $\frac{2 π m}{q B}$
$Solution :$
Equating magnetic force to centripetal force,we get
$\frac{m v^{2}}{r} = q v B s i n 90^{\circ}$
Also,Time to complete one revolution is given by,
$T = \frac{2 π r}{v} = \frac{2 π m}{q B}$

$Hence C is the correct option$